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Elliptic Curve Addition

Modern cryptography runs on a strange kind of arithmetic where you add points on a curve. See the elegant geometric rule that secures Bitcoin and TLS.

Elliptic Curve AdditionLive

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On an elliptic curve y² = x³ + ax + b, you "add" two points with a geometric rule: draw the line through P and Q, find where it meets the curve again, and reflect that point over the x-axis. Repeating this addition is easy, but reversing it — the elliptic-curve discrete log — is brutally hard, which is what makes ECC secure with far smaller keys than RSA.

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Data Inspector

Slope-0.14
P+Q (x)0.52
P+Q (y)-0.79

Governing equation

Reading this result: The secant through P and Q meets the curve at a third point; reflecting it across the x-axis gives P+Q. Repeating this is easy, but undoing it (the discrete log) is what secures ECC.

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How it works

On an elliptic curve y² = x³ + ax + b, adding two points means drawing the line through them, finding the third intersection with the curve, and reflecting it over the x-axis. Repeating this scalar multiplication is fast, but undoing it — the elliptic-curve discrete logarithm — is infeasible. That asymmetry gives ECC RSA-grade security with far smaller keys, ideal for phones and embedded devices.

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Frequently asked questions

Is this elliptic curve cryptography addition tool really free?
Yes. Elliptic Curve Addition runs entirely in your browser using your device's own compute, so local use is free forever. You only pay Compute Tokens if you scale a job to the cloud.
Do I need to install anything?
No. Everything runs client-side in a modern browser — no downloads, no license, no account required to start.
Can I save or share my simulation?
Create a free account to save projects, and use a shareable embed or minted DOI to publish a live, interactive version anywhere.
How accurate are the results?
The solver uses established numerical methods, but results are for research and educational purposes and should be validated against experiment or professional review before you rely on them.